Normal Distribution and z-Scores: How to Read a Percentile
"You scored above 93% of people" sounds intuitive, but it comes from a two-step conversion: turn the score into a z-score, then read the normal distribution. Understand those steps and percentile claims stop being mysterious.
What the normal distribution describes
Many natural and measured quantities form a bell: common in the middle, rare at the tails, roughly symmetric, fully determined by the mean μ (centre) and standard deviation σ (spread).
A larger σ flattens the curve. Same mean and same σ means the same whole curve — which is why a mean alone is never enough.
The 68–95–99.7 rule
- About 68.3% of values fall within μ ± 1σ
- About 95.4% within μ ± 2σ
- About 99.7% within μ ± 3σ
So "two standard deviations above the mean" leaves roughly 2.3% above you ((100 − 95.4) ÷ 2 ≈ 2.3%). Remember to halve it — you want one tail, not both.
From z-score to percentile
z = (x − μ) ÷ σ counts standard deviations from the mean. Common conversions:
- z = 0 → 50th percentile
- z = 1 → 84.1st
- z = 1.5 → 93.3rd
- z = 1.96 → 97.5th (the two-sided 95% cutoff)
- z = −1 → 15.9th
A worked exam example
Class mean 70, SD 10, you scored 85:
z = (85 − 70) ÷ 10 = 1.5 → about the 93.3rd percentile, above roughly 93% of the class.
In another class with mean 75 and SD 5, the same 85 gives z = 2 → 97.7th percentile. The same raw score means something different in each class — which is why raw marks alone cannot rank people.
When this framework fails
- Strong skew: income, house prices and dwell time are right-skewed; normal-based percentiles mislead badly.
- Small samples: an SD estimated from a dozen points is unstable, so z-scores are too.
- Outliers: one extreme value inflates both mean and SD and flattens everyone else’s z.
- Non-independent data: repeated measures on the same people change the standard error and assumptions.
Safer with enough data: use the empirical percentile (rank after sorting) — it assumes no distribution at all.
This article provides general information and calculation methods only. It is not medical, investment or legal advice; consult a qualified professional for your situation.